C Programming - Floating Point Issues - Discussion

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"Everything should be made as simple as possible, but not simpler."

- Albert Einstein

What will be the output of the program?

#include<stdio.h>
#include<math.h>
int main()
{
    float n=1.54;
    printf("%f, %f\n", ceil(n), floor(n));
    return 0;
}

[A].	2.000000, 1.000000	[B].	1.500000, 1.500000
[C].	1.550000, 2.000000	[D].	1.000000, 2.000000

Answer: Option B

Explanation:

ceil(x) round up the given value. It finds the smallest integer not < x.
floor(x) round down the given value. It finds the smallest integer not > x.

printf("%f, %f\n", ceil(n), floor(n)); In this line ceil(1.54) round up the 1.54 to 2 and floor(1.54) round down the 1.54 to 1.

In the printf("%f, %f\n", ceil(n), floor(n)); statement, the format specifier "%f %f" tells output to be float value. Hence it prints 2.000000 and 1.000000.

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C Programming - Floating Point Issues - Discussion

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