Online Aptitude Test - Aptitude Test - Random



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Instruction:

  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).


Direction (for Q.No. 1):

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and

  • Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
  • Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
  • Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
  • Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
  • Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
1.

What is Sonia's present age?

I. 

Sonia's present age is five times Deepak's present age.

 II. 

Five years ago her age was twenty-five times Deepak's age at that time.

A.
I alone sufficient while II alone not sufficient to answer
B.
II alone sufficient while I alone not sufficient to answer
C.
Either I or II alone sufficient to answer
D.
Both I and II are not sufficient to answer
E.
Both I and II are necessary to answer

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

 I. S = 5D    D = S ....(i)
5

II. S - 5 = 25 (D - 5)    S = 25D - 120 ....(ii)

Using (i) in (ii), we get S = 25 x S - 120
5

4S = 120.

S = 30.

Thus, I and II both together give the answer. So, correct answer is (E).

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2.

A man invests some money partly in 9% stock at 96 and partly in 12% stock at 120. To obtain equal dividends from both, he must invest the money in the ratio:

A.
3 : 4
B.
3 : 5
C.
4 : 5
D.
16 : 15

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

For an income of Re. 1 in 9% stock at 96, investment = Rs. 96 = Rs. 32
9 3

For an income Re. 1 in 12% stock at 120, investment = Rs. 120 = Rs. 10.
12

Ratio of investments = 32 : 10 = 32 : 30 = 16 : 15.
3

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3.

Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?

A.
24
B.
27
C.
40
D.
Cannot be determined
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

Then, 5x + 3 = 11
4x + 3 9

9(5x + 3) = 11(4x + 3)

45x + 27 = 44x + 33

45x - 44x = 33 - 27

x = 6.

Anand's present age = 4x = 24 years.

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4.

Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:

A.
9
B.
9.6
C.
10
D.
10.8

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Relative speed = (60 + 40) km/hr = 100 x 5 m/sec = 250 m/sec.
18 9

Distance covered in crossing each other = (140 + 160) m = 300 m.

Required time = 300 x 9 sec = 54 sec = 10.8 sec.
250 5

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5.

If a - b = 3 and a2 + b2 = 29, find the value of ab.

A.
10
B.
12
C.
15
D.
18

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

2ab = (a2 + b2) - (a - b)2

   = 29 - 9 = 20

   ab = 10.

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6.

Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is:

A.
30%
B.
33 1 %
3
C.
35%
D.
44%

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.

C.P. of 30 articles = Rs. 5 x 30 = Rs. 25.
6

S.P. of 30 articles = Rs. 6 x 30 = Rs. 36.
5

Gain % = 11 x 100 % = 44%.
25

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Direction (for Q.Nos. 7 - 8):
Find out the wrong number in the series.
7.

3, 7, 15, 27, 63, 127, 255

A.
7
B.
15
C.
27
D.
63
E.
127

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Go on multiplying the number by 2 and adding 1 to it to get the next number.

So, 27 is wrong.

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8.

7, 8, 18, 57, 228, 1165, 6996

A.
8
B.
18
C.
57
D.
228
E.
1165

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Let the given numbers be A, B, C, D, E, F, G.

Then, A, A x 1 + 1, B x 2 + 2, C x 3 + 3, D x 4 + 4, E x 5 + 5, F x 6 + 6 are the required numbers.

Clearly, 228 is wrong.

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9.

The rational number for recurring decimal 0.125125.... is:

A.
63
487
B.
119
993
C.
125
999
D.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

0.125125... = 0.125 = 125
999

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10.

The value of (0.96)3 - (0.1)3 is:
(0.96)2 + 0.096 + (0.1)2

A.
0.86
B.
0.95
C.
0.97
D.
1.06

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Given expression
= (0.96)3 - (0.1)3
(0.96)2 + (0.96 x 0.1) + (0.1)2
= a3 - b3
a2 + ab + b2
= (a - b)
= (0.96 - 0.1)
= 0.86

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11.

The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:

A.
123
B.
127
C.
235
D.
305

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Required number = H.C.F. of (1657 - 6) and (2037 - 5)

  = H.C.F. of 1651 and 2032 = 127.

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12.

If log10 5 + log10 (5x + 1) = log10 (x + 5) + 1, then x is equal to:

A.
1
B.
3
C.
5
D.
10

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

log10 5 + log10 (5x + 1) = log10 (x + 5) + 1

log10 5 + log10 (5x + 1) = log10 (x + 5) + log10 10

log10 [5 (5x + 1)] = log10 [10(x + 5)]

5(5x + 1) = 10(x + 5)

5x + 1 = 2x + 10

3x = 9

x = 3.

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13.

The last day of a century cannot be

A.
Monday
B.
Wednesday
C.
Tuesday
D.
Friday

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

100 years contain 5 odd days.

Last day of 1st century is Friday.

200 years contain (5 x 2) 3 odd days.

Last day of 2nd century is Wednesday.

300 years contain (5 x 3) = 15 1 odd day.

Last day of 3rd century is Monday.

400 years contain 0 odd day.

Last day of 4th century is Sunday.

This cycle is repeated.

Last day of a century cannot be Tuesday or Thursday or Saturday.

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14.

What was the day of the week on 17th June, 1998?

A.
Monday
B.
Tuesday
C.
Wednesday
D.
Thursday

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan.  Feb.   March    April    May      June 
(31 +  28  +  31   +   30   +   31   +   17) = 168 days

168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.

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15.

At a game of billiards, A can give B 15 points in 60 and A can give C to 20 points in 60. How many points can B give C in a game of 90?

A.
30 points
B.
20 points
C.
10 points
D.
12 points

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

A : B = 60 : 45.

A : C = 60 : 40.

B = B x A = 45 x 60 = 45 = 90 = 90 : 80.
C A C 60 40 40 80

B can give C 10 points in a game of 90.

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16.

A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?

A.
Rs. 4462.50
B.
Rs. 8032.50
C.
Rs. 8900
D.
Rs. 8925
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Principal
= Rs. 100 x 4016.25
9 x 5
= Rs. 401625
45
= Rs. 8925.

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17.

A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is:

A.
5%
B.
8%
C.
12%
D.
15%

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

S.I. for 3 years = Rs. (12005 - 9800) = Rs. 2205.

S.I. for 5 years = Rs. 2205 x 5 = Rs. 3675
3

Principal = Rs. (9800 - 3675) = Rs. 6125.

Hence, rate = 100 x 3675 % = 12%
6125 x 5

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Direction (for Q.No. 18):
Find out the wrong number in the given sequence of numbers.
18.

36, 54, 18, 27, 9, 18.5, 4.5

A.
4.5
B.
18.5
C.
54
D.
18

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

The terms are alternatively multiplied by 1.5 and divided by 3. However, 18.5 does not satisfy it.

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19.

A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit.

A.
Rs. 1900
B.
Rs. 2660
C.
Rs. 2800
D.
Rs. 2840

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

For managing, A received = 5% of Rs. 7400 = Rs. 370.

Balance = Rs. (7400 - 370) = Rs. 7030.

Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3)

   = 39000 : 42000 : 30000

   = 13 : 14 : 10

B's share = Rs. 7030 x 14 = Rs. 2660.
37

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20.

A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

A.
4 litres, 8 litres
B.
6 litres, 6 litres
C.
5 litres, 7 litres
D.
7 litres, 5 litres

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let the cost of 1 litre milk be Re. 1

Milk in 1 litre mix. in 1st can = 3 litre, C.P. of 1 litre mix. in 1st can Re. 3
4 4

Milk in 1 litre mix. in 2nd can = 1 litre, C.P. of 1 litre mix. in 2nd can Re. 1
2 2

Milk in 1 litre of final mix. = 5 litre, Mean price = Re. 5
8 8

By the rule of alligation, we have:

C.P. of 1 litre mixture in 1st can    C.P. of 1 litre mixture in 2nd can
3
4
Mean Price
5
8
1
2
1
8
1
8

Ratio of two mixtures = 1 : 1 = 1 : 1.
8 8

So, quantity of mixture taken from each can = 1 x 12 = 6 litres.
2

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