# Online Aptitude Test - Aptitude Test - Random

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Instruction:

• Total number of questions : 20.
• Time alloted : 30 minutes.
• Each question carry 1 mark, no negative marks.
• DO NOT refresh the page.
• All the best :-).

1.

A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is:

A.
 1 3
B.
 2 3
C.
 2 5
D.
 3 5

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

By the rule of alligation, we have:

 Strength of first jar Strength of 2nd jar 40% MeanStrength 26% 19% 7 14

So, ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2

 Required quantity replaced = 2 3

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2.

In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:

A.
 60 m
B.
 40 m
C.
 20 m
D.
 10 m

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.

While A covers 3 m, B covers 4 m.

 While A covers 360 m, B covers 4 x 360 m = 480 m. 3

Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.

A wins by 20 m.

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3.

In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:

A.
 5.4 m
B.
 4.5 m
C.
 5 m
D.
 6 m

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

A : B = 100 : 90.

A : C = 100 : 87.

 B = B x A = 90 x 100 = 30 . C A C 100 87 29

When B runs 30 m, C runs 29 m.

 When B runs 180 m, C runs 29 x 180 m = 174 m. 30

B beats C by (180 - 174) m = 6 m.

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Direction (for Q.No. 4):

Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and

• Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
• Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
• Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
• Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
• Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
4.

 Two cars pass each other in opposite direction. How long would they take to be 500 km apart? I. The sum of their speeds is 135 km/hr. II. The difference of their speed is 25 km/hr.

A.
 I alone sufficient while II alone not sufficient to answer
B.
 II alone sufficient while I alone not sufficient to answer
C.
 Either I or II alone sufficient to answer
D.
 Both I and II are not sufficient to answer
E.
 Both I and II are necessary to answer

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

I gives, relative speed = 135 km/hr.

 Time taken = 500 hrs. 135

II does not give the relative speed.

I alone gives the answer and II is irrelevant.

Correct answer is (A).

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5.

In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?

A.
 50
B.
 100
C.
 150
D.
 200

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.

 Then, sum of their values = Rs. 25x + 10 x 2x + 5 x 3x = Rs. 60x 100 100 100 100

 60x = 30 x = 30 x 100 = 50. 100 60

Hence, the number of 5 p coins = (3 x 50) = 150.

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6.

A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:

A.
 Rs. 12
B.
 Rs. 15
C.
 Rs. 18
D.
 Rs. 21

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

 Dividend on Rs. 20 = Rs. 9 x 20 = Rs. 9 . 100 5

Rs. 12 is an income on Rs. 100.

 Rs. 9 is an income on Rs. 100 x 9 = Rs. 15. 5 12 5

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7.

Three unbiased coins are tossed. What is the probability of getting at most two heads?

A.
 3 4
B.
 1 4
C.
 3 8
D.
 7 8

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

 P(E) = n(E) = 7 . n(S) 8

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8.

Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?

A.
 24
B.
 27
C.
 40
D.
 Cannot be determined
E.
 None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

 Then, 5x + 3 = 11 4x + 3 9

9(5x + 3) = 11(4x + 3)

45x + 27 = 44x + 33

45x - 44x = 33 - 27

x = 6.

Anand's present age = 4x = 24 years.

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9.

An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:

A.
 2%
B.
 2.02%
C.
 4%
D.
 4.04%

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

100 cm is read as 102 cm.

A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.

(A2 - A1) = [(102)2 - (100)2]

= (102 + 100) x (102 - 100)

= 404 cm2.

 Percentage error = 404 x 100 % = 4.04% 100 x 100

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Direction (for Q.Nos. 10 - 11):
Insert the missing number.
10.

4, -8, 16, -32, 64, (....)

A.
 128
B.
 -128
C.
 192
D.
 -192

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Each number is the proceeding number multiplied by -2.

So, the required number is -128.

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11.

16, 33, 65, 131, 261, (....)

A.
 523
B.
 521
C.
 613
D.
 721

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Each number is twice the preceding one with 1 added or subtracted alternatively.

So, the next number is (2 x 261 + 1) = 523.

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12.

If a - b = 3 and a2 + b2 = 29, find the value of ab.

A.
 10
B.
 12
C.
 15
D.
 18

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

2ab = (a2 + b2) - (a - b)2

= 29 - 9 = 20

ab = 10.

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13.

How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?

A.
 5600
B.
 6000
C.
 6400
D.
 7200

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

 Number of bricks = Volume of the wall = 800 x 600 x 22.5 = 6400. Volume of 1 brick 25 x 11.25 x 6

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14.

 Reduce 128352 to its lowest terms. 238368

A.
 3 4
B.
 5 13
C.
 7 13
D.
 9 13

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

``` 128352) 238368 ( 1
128352
---------------
110016 ) 128352 ( 1
110016
------------------
18336 ) 110016 ( 6
110016
-------
x
-------
So, H.C.F. of 128352 and 238368 = 18336.

128352     128352 ÷ 18336    7
Therefore,  ------  =  -------------- =  --
238368     238368 ÷ 18336    13
```

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15.

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

A.
 159
B.
 194
C.
 205
D.
 209
E.
 None of these

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys).

Required number
of ways
= (6C1 x 4C3) + (6C2 x 4C2) + (6C3 x 4C1) + (6C4)
= (6C1 x 4C1) + (6C2 x 4C2) + (6C3 x 4C1) + (6C2)
 = (6 x 4) + 6 x 5 x 4 x 3 + 6 x 5 x 4 x 4 + 6 x 5 2 x 1 2 x 1 3 x 2 x 1 2 x 1
= (24 + 90 + 80 + 15)
= 209.

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16.

Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

A.
 210
B.
 1050
C.
 25200
D.
 21400
E.
 None of these

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)

= (7C3 x 4C2)
 = 7 x 6 x 5 x 4 x 3 3 x 2 x 1 2 x 1
= 210.

Number of groups, each having 3 consonants and 2 vowels = 210.

Each group contains 5 letters.

 Number of ways of arranging 5 letters among themselves = 5! = 5 x 4 x 3 x 2 x 1 = 120.

Required number of ways = (210 x 120) = 25200.

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17.

A began a business with Rs. 85,000. He was joined afterwards by B with Rs. 42,500. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1?

A.
 4 months
B.
 5 months
C.
 6 months
D.
 8 months

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Suppose B joined for x months. Then,

 Then, 85000 x 12 = 3 42500 x x 1

 x = 85000 x 12 = 8. 42500 x 3

So, B joined for 8 months.

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Direction (for Q.No. 18):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

18.

 What will be the compound interest earned on an amount of Rs. 5000 in 2 years? I. The simple interest on the same amount at the same rate of interest in 5 years is Rs. 2000. II. The compound interest and the simple interest earned in one year is the same. III. The amount becomed more than double on compound interest in 10 years.

A.
 I only
B.
 I and II only
C.
 II and III only
D.
 I and III only
E.
 None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

P = Rs. 5000 & T = 2 years.

I. S.I. on Rs. 5000 in 5 years is Rs. 2000.

 5000 x R x 5 = 2000         R = 8. 100

Thus I only gives the answer.

Correct answer is (A).

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19.

What will be the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 9 years?

A.
 1 : 3
B.
 1 : 4
C.
 2 : 3
D.
 Data inadequate
E.
 None of these

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the principal be P and rate of interest be R%.

Required ratio =
 P x R x 6 100
= 6PR = 6 = 2 : 3.
 P x R x 9 100
9PR 9

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20.

A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in:

A.

 9 1 days 5

B.

 9 2 days 5

C.

 9 3 days 5

D.
 10

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

 (A + B + C)'s 1 day's work = 1 , 4

 A's 1 day's work = 1 , 16

 B's 1 day's work = 1 . 12

 C's 1 day's work = 1 - 1 + 1 = 1 - 7 = 5 . 4 16 12 4 48 48

 So, C alone can do the work in 48 = 9 3 days. 5 5

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