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 Total number of questions : 20.
 Time alloted : 30 minutes.
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Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
 
1. 


Your Answer: Option (Not Answered) Correct Answer: Option E Explanation:
II. S  5 = 25 (D  5) S = 25D  120 ....(ii)
4S = 120. S = 30. Thus, I and II both together give the answer. So, correct answer is (E). Learn more problems on : Problems on Ages Discuss about this problem : Discuss in Forum 
2.  A man invests some money partly in 9% stock at 96 and partly in 12% stock at 120. To obtain equal dividends from both, he must invest the money in the ratio: 

Your Answer: Option (Not Answered) Correct Answer: Option D Explanation:
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3.  Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years? 

Your Answer: Option (Not Answered) Correct Answer: Option A Explanation: Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
9(5x + 3) = 11(4x + 3) 45x + 27 = 44x + 33 45x  44x = 33  27 x = 6. Anand's present age = 4x = 24 years. Learn more problems on : Problems on Ages Discuss about this problem : Discuss in Forum 
4.  Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is: 

Your Answer: Option (Not Answered) Correct Answer: Option D Explanation:
Distance covered in crossing each other = (140 + 160) m = 300 m.
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5.  If a  b = 3 and a^{2} + b^{2} = 29, find the value of ab. 

Your Answer: Option (Not Answered) Correct Answer: Option A Explanation: 2ab = (a^{2} + b^{2})  (a  b)^{2} = 29  9 = 20 ab = 10. Learn more problems on : Simplification Discuss about this problem : Discuss in Forum 
6.  Some articles were bought at 6 articles for Rs. 5 and sold at 5 articles for Rs. 6. Gain percent is: 

Your Answer: Option (Not Answered) Correct Answer: Option D Explanation: Suppose, number of articles bought = L.C.M. of 6 and 5 = 30.
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Find out the wrong number in the series.  
7.  3, 7, 15, 27, 63, 127, 255 

Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: Go on multiplying the number by 2 and adding 1 to it to get the next number. So, 27 is wrong. Learn more problems on : Odd Man Out and Series Discuss about this problem : Discuss in Forum 
8.  7, 8, 18, 57, 228, 1165, 6996 

Your Answer: Option (Not Answered) Correct Answer: Option D Explanation: Let the given numbers be A, B, C, D, E, F, G. Then, A, A x 1 + 1, B x 2 + 2, C x 3 + 3, D x 4 + 4, E x 5 + 5, F x 6 + 6 are the required numbers. Clearly, 228 is wrong. Learn more problems on : Odd Man Out and Series Discuss about this problem : Discuss in Forum 
9.  The rational number for recurring decimal 0.125125.... is: 

Your Answer: Option (Not Answered) Correct Answer: Option C Explanation:
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10. 


Your Answer: Option (Not Answered) Correct Answer: Option A Explanation:
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11.  The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: 

Your Answer: Option (Not Answered) Correct Answer: Option B Explanation: Required number = H.C.F. of (1657  6) and (2037  5) = H.C.F. of 1651 and 2032 = 127. Learn more problems on : Problems on H.C.F and L.C.M Discuss about this problem : Discuss in Forum 
12.  If log_{10} 5 + log_{10} (5x + 1) = log_{10} (x + 5) + 1, then x is equal to: 

Your Answer: Option (Not Answered) Correct Answer: Option B Explanation: log_{10} 5 + log_{10} (5x + 1) = log_{10} (x + 5) + 1 log_{10} 5 + log_{10} (5x + 1) = log_{10} (x + 5) + log_{10} 10 log_{10} [5 (5x + 1)] = log_{10} [10(x + 5)] 5(5x + 1) = 10(x + 5) 5x + 1 = 2x + 10 3x = 9 x = 3. Learn more problems on : Logarithm Discuss about this problem : Discuss in Forum 
13.  The last day of a century cannot be 

Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: 100 years contain 5 odd days. Last day of 1^{st} century is Friday. 200 years contain (5 x 2) 3 odd days. Last day of 2^{nd} century is Wednesday. 300 years contain (5 x 3) = 15 1 odd day. Last day of 3^{rd} century is Monday. 400 years contain 0 odd day. Last day of 4^{th} century is Sunday. This cycle is repeated. Last day of a century cannot be Tuesday or Thursday or Saturday. Learn more problems on : Calendar Discuss about this problem : Discuss in Forum 
14.  What was the day of the week on 17^{th} June, 1998? 

Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: 17^{th} June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998) Odd days in 1600 years = 0 Odd days in 300 years = (5 x 3) 1 97 years has 24 leap years + 73 ordinary years. Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March April May June (31 + 28 + 31 + 30 + 31 + 17) = 168 days 168 days = 24 weeks = 0 odd day. Total number of odd days = (0 + 1 + 2 + 0) = 3. Given day is Wednesday. Learn more problems on : Calendar Discuss about this problem : Discuss in Forum 
15.  At a game of billiards, A can give B 15 points in 60 and A can give C to 20 points in 60. How many points can B give C in a game of 90? 

Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: A : B = 60 : 45. A : C = 60 : 40.
B can give C 10 points in a game of 90. Learn more problems on : Races and Games Discuss about this problem : Discuss in Forum 
16.  A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum? 

Your Answer: Option (Not Answered) Correct Answer: Option D Explanation:
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17.  A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is: 

Your Answer: Option (Not Answered) Correct Answer: Option C Explanation: S.I. for 3 years = Rs. (12005  9800) = Rs. 2205.
Principal = Rs. (9800  3675) = Rs. 6125.
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Find out the wrong number in the given sequence of numbers.  
18.  36, 54, 18, 27, 9, 18.5, 4.5 

Your Answer: Option (Not Answered) Correct Answer: Option B Explanation:
The terms are alternatively multiplied by 1.5 and divided by 3. However, 18.5 does not satisfy it.
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19.  A, B and C jointly thought of engaging themselves in a business venture. It was agreed that A would invest Rs. 6500 for 6 months, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A wants to be the working member for which, he was to receive 5% of the profits. The profit earned was Rs. 7400. Calculate the share of B in the profit. 

Your Answer: Option (Not Answered) Correct Answer: Option B Explanation: For managing, A received = 5% of Rs. 7400 = Rs. 370. Balance = Rs. (7400  370) = Rs. 7030. Ratio of their investments = (6500 x 6) : (8400 x 5) : (10000 x 3) = 39000 : 42000 : 30000 = 13 : 14 : 10
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20.  A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5? 

Your Answer: Option (Not Answered) Correct Answer: Option B Explanation: Let the cost of 1 litre milk be Re. 1
By the rule of alligation, we have:
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