Online Aptitude Test - Aptitude Test - Random

 4 | x            z = 6 x 1 + 4  = 10
 -----------
 5 | y -2         y = 5 x z + 3  = 5 x 10 + 3  = 53
 -----------
 6 | z - 3        x = 4 x y + 2  = 4 x 53 + 2  = 214
 -----------
   | 1 - 4
   
Hence, required number = 214.

S_n = (1 + 2 + 3 + ... + 50 + 51 + 52 + ... + 100) - (1 + 2 + 3 + ... + 50)

    = (50 x 101) - (25 x 51)

    = (5050 - 1275)

    = 3775.

 128352) 238368 ( 1
         128352
         ---------------
         110016 ) 128352 ( 1
                  110016
                 ------------------  
                   18336 ) 110016 ( 6       
                           110016
                           -------
                                x
                           -------
 So, H.C.F. of 128352 and 238368 = 18336.
 
             128352     128352 ÷ 18336    7
 Therefore,  ------  =  -------------- =  --
             238368     238368 ÷ 18336    13                    

Let the ten's digit be x and unit's digit be y.

Then, x + y = 15 and x - y = 3   or   y - x = 3.

Solving x + y = 15   and   x - y = 3, we get: x = 9, y = 6.

Solving x + y = 15   and   y - x = 3, we get: x = 6, y = 9.

So, the number is either 96 or 69.

Hence, the number cannot be determined.

I. S = 5D    D =	S	....(i)
	5

II. S - 5 = 25 (D - 5)    S = 25D - 120 ....(ii)

Using (i) in (ii), we get S =		25 x	S		- 120
			5

4S = 120.

S = 30.

Thus, I and II both together give the answer. So, correct answer is (E).

(0.04)-1.5 =		4		-1.5
		100

=		1		-(3/2)
		25

   = (25)^(3/2)

   = (5²)^(3/2)

   = (5)^{2 x (3/2)}

   = 5³

   = 125.

85 : 18700 = 115 : x

x =		18700 x 115		= 25300.
		85

Hence, S.P. = Rs. 25,300.

Work done by X in 4 days =		1	x 4		=	1	.
		20				5

Remaining work =		1 -	1		=	4	.
			5			5

(X + Y)'s 1 day's work =		1	+	1		=	8	=	2	.
		20		12			60		15

So,	4	work will be done by X and Y in		15	x	4		= 6 days.
	5			2		5

Hence, total time taken = (6 + 4) days = 10 days.

From II and III, we get:

8y = 24 + 6y

y = 12.

Required speed =	1	(12 + 4) km/hr = 8 km/hr.
	2

Similarly, I and III also give the answer.

Correct answer is (D).

2l + 2b = 5b

3b = 2l

Then, Area = 216 cm²

l x b = 216

l x	2	l	= 216
	3

l² = 324

l = 18 cm.

From II, base : height = 5 : 12.

Let base = 5x and height = 12x.

Then, hypotenuse = (5x)² + (12x)² = 13x.

From I, perimeter of the triangle = 30 cm.

5x + 12x + 13x = 30         x = 1.

So, base = 5x = 5 cm, height = 12x = 12 cm.

Area =		1	x 5 x 12	cm2	= 30 cm2.
		2

Thus, I and II together give the answer.

Clearly III is redundant, since the breadth of the rectangle is not given.

Correct answer is (A).

To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.

While A covers 3 m, B covers 4 m.

While A covers 360 m, B covers		4	x 360	m	= 480 m.
		3

Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.

A wins by 20 m.

A : B = 100 : 80.

A : C = 100 : 72.

B

=

B

x

A

=

80

x

100

=

10

=

100

= 100 : 90.

C

A

C

100

72

9

90

B can give C 10 points.

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

After 61 days, it will be Saturday.

Angle traced by hour hand in 12 hrs = 360°.

Angle traced by hour hand in 5 hrs 10 min. i.e.,	31	hrs =		360	x	31		°	= 155°.
	6			12		6

In two throws of a dice, n(S) = (6 x 6) = 36.

Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.

P(E) =	n(E)	=	4	=	1	.
	n(S)		36		9

P.W. = Rs. (1760 -160) = Rs. 1600.

S.I. on Rs. 1600 at 12% is Rs. 160.

Time =		100 x 160		=	5	years =		5	x 12	months = 10 months.
		1600 x 12			6			6

Numbers are alternatively multiplied by 3 and divided by 2.

So, the next number = 54 ÷ 2 = 27.