Online Aptitude Test - Aptitude Test - Random



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Instruction:

  • Total number of questions : 20.
  • Time alloted : 30 minutes.
  • Each question carry 1 mark, no negative marks.
  • DO NOT refresh the page.
  • All the best :-).

1.

The banker's gain of a certain sum due 2 years hence at 10% per annum is Rs. 24. The present worth is:

A.
Rs. 480
B.
Rs. 520
C.
Rs. 600
D.
Rs. 960

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

T.D. = B.G. x 100 = Rs. 24 x 100 = Rs. 120.
Rate x Time 10 x 2

P.W. = 100 x T.D. = Rs. 100 x 120 = Rs. 600.
Rate x Time 10 x 2

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2.

The banker's discount on a certain sum due 2 years hence is 11 of the true discount.
10

The rate percent is:

A.
11%
B.
10%
C.
5%
D.
5.5%

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let T.D. be Re. 1.

Then, B.D. = Rs. 11 = Rs. 1.10.
10

Sum = Rs. 1.10 x 1 = Rs. 110 = Rs. 11.
1.10 - 1 10

S.I. on Rs. 11 for 2 years is Rs. 1.10

Rate = 100 x 1.10 % = 5%.
11 x 2

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3.

When a plot is sold for Rs. 18,700, the owner loses 15%. At what price must that plot be sold in order to gain 15%?

A.
Rs. 21,000
B.
Rs. 22,500
C.
Rs. 25,300
D.
Rs. 25,800

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

85 : 18700 = 115 : x

x = 18700 x 115 = 25300.
85

Hence, S.P. = Rs. 25,300.

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4.

(469 + 174)2 - (469 - 174)2 = ?
(469 x 174)

A.
2
B.
4
C.
295
D.
643

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Given exp. = (a + b)2 - (a - b)2
ab

   = 4ab
ab

   = 4 (where a = 469, b = 174.)

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5.

A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:

A.
14 years
B.
19 years
C.
33 years
D.
38 years

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

Let the son's present age be x years. Then, (38 - x) = x

2x = 38.

x = 19.

Son's age 5 years back (19 - 5) = 14 years.

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6.

In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:

A.
21 m
B.
26 m
C.
28 m
D.
29 m

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

A : B = 100 : 75

B : C = 100 : 96.

A : C = A x B = 100 x 100 = 100 = 100 : 72.
B C 75 96 72

A beats C by (100 - 72) m = 28 m.

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7.

A merchant has 1000 kg of sugar, part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The quantity sold at 18% profit is:

A.
400 kg
B.
560 kg
C.
600 kg
D.
640 kg

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

By the rule of alligation, we have:

Profit on 1st part Profit on 2nd part
8% Mean Profit
14%
18%
4 6

Ration of 1st and 2nd parts = 4 : 6 = 2 : 3

Quantity of 2nd kind = 3 x 1000 kg = 600 kg.
5

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8.

A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:

A.
18
B.
24
C.
42
D.
81

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let the ten's and unit digit be x and 8 respectively.
x

Then, 10x + 8 + 18 = 10 x 8 + x
x x

10x2 + 8 + 18x = 80 + x2

9x2 + 18x - 72 = 0

x2 + 2x - 8 = 0

(x + 4)(x - 2) = 0

x = 2.

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9.

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is:

A.
2 : 3
B.
3 : 2
C.
3 : 4
D.
4 : 3

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the speed of the train be x km/hr and that of the car be y km/hr.

Then, 120 + 480 = 8       1 + 4 = 1 ....(i)
x y x y 15

And, 200 + 400 = 25     1 + 2 = 1 ....(ii)
x y 3 x y 24

Solving (i) and (ii), we get: x = 60 and y = 80.

Ratio of speeds = 60 : 80 = 3 : 4.

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10.

A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?

A.
5
B.

5 1
2

C.
6
D.
8

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

B's 10 day's work = ( 1 x 10 ) = 2 .
15 3

Remaining work = ( 1 - 2 ) = 1 .
3 3

Now, 1 work is done by A in 1 day.
18

Therefore 1 work is done by A in ( 18 x 1 ) = 6 days.
3 3

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Direction (for Q.No. 11):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

11.

What is the two-digit number?

I. 

The difference between the two-digit number and the number formed by interchanging the digits is 27.

II. 

The difference between the two digits is 3.

 III. 

The digit at unit's place is less than that at ten's place by 3.

A.
I and II only
B.
I and III only
C.
All I, II and III
D.
I, and either II or III
E.
Even with all I, II and III, answer cannot be give.

Your Answer: Option (Not Answered)

Correct Answer: Option E

Explanation:

Let the tens and units digit be x and y respectively.

  I. (10x + y) - (10y + x)       x - y = 3.

 II. x - y = 3.

III. x - y = 3.

Thus, even all the given three statements together do not give the answer.

Correct answer is (E).

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12.

A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

A.
120 metres
B.
180 metres
C.
324 metres
D.
150 metres

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

Speed= 60 x 5 m/sec = 50 m/sec.
18 3

Length of the train = (Speed x Time).

Length of the train = 50 x 9 m = 150 m.
3

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13.

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?

A.
10
B.
12
C.
15
D.
20

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Speed of the first train = ( 120 ( m/sec = 12 m/sec.
10

Speed of the second train = ( 120 ( m/sec = 8 m/sec.
15

Relative speed = (12 + 8) = 20 m/sec.

Therefore Required time = [ (120 + 120) ] sec = 12 sec.
20

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14.

A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be:

A.
10 m
B.
12.5 m
C.
17.5 m
D.
21.25 m

Your Answer: Option (Not Answered)

Correct Answer: Option B

Explanation:

Let the height of the building x metres.

Less lengthy shadow, Less in the height (Direct Proportion)

40.25 : 28.75 :: 17.5 : x       40.25 x x = 28.75 x 17.5

x = 28.75 x 17.5
40.25

x = 12.5

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15.

On what dates of April, 2001 did Wednesday fall?

A.
1st, 8th, 15th, 22nd, 29th
B.
2nd, 9th, 16th, 23rd, 30th
C.
3rd, 10th, 17th, 24th
D.
4th, 11th, 18th, 25th

Your Answer: Option (Not Answered)

Correct Answer: Option D

Explanation:

We shall find the day on 1st April, 2001.

1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)

Odd days in 1600 years = 0

Odd days in 400 years = 0

Jan. Feb. March April
(31 + 28 + 31 + 1)     = 91 days 0 odd days.

Total number of odd days = (0 + 0 + 0) = 0

On 1st April, 2001 it was Sunday.

In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.

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Direction (for Q.No. 16):
Find out the wrong number in the series.
16.

3, 7, 15, 27, 63, 127, 255

A.
7
B.
15
C.
27
D.
63
E.
127

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Go on multiplying the number by 2 and adding 1 to it to get the next number.

So, 27 is wrong.

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17.

At what angle the hands of a clock are inclined at 15 minutes past 5?

A.
58 1
2
B.
64
C.
67 1
2
D.
72 1
2

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Angle traced by hour hand in 21 hrs = 360 x 21 = 157 1
4 12 4 2

Angle traced by min. hand in 15 min. = 360 x 15 = 90.
60

Required angle = 157 1 - 90 = 67 1
2 2

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Direction (for Q.No. 18):

Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.

18.

By selling an article what is the profit percent gained?

I. 

5% discount is given on list price.

II. 

If discount is not given, 20% profit is gained.

 III. 

The cost price of the articles is Rs. 5000.

A.
Only I and II
B.
Only II and III
C.
Only I and III
D.
All I, II and III
E.
None of these

Your Answer: Option (Not Answered)

Correct Answer: Option A

Explanation:

 I. Let the list price be Rs. x.

Then, S.P. = 95% of Rs. x = Rs. x x 95 = Rs. 19x
100 20

II. When S.P. = Rs. x and gain = 20%.

Then, C.P. = Rs. 100 x x = Rs. 5x
120 6

Gain = 19x - 5x = 57x - 50x = 7x
20 6 60 60

Gain % = 7x x 6 x 100 % = 14%.
60 5x

Thus, I and II only give the answer.

Correct answer is (A).

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19.

A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

A.
20
B.
24
C.
30
D.
33

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

Let the side of the square(ABCD) be x metres.

Then, AB + BC = 2x metres.

AC = 2x = (1.41x) m.

Saving on 2x metres = (0.59x) m.

Saving % = 0.59x x 100 % = 30% (approx.)
2x

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Direction (for Q.No. 20):
Find the odd man out.
20.

1, 4, 9, 16, 20, 36, 49

A.
1
B.
9
C.
20
D.
49

Your Answer: Option (Not Answered)

Correct Answer: Option C

Explanation:

The pattern is 12, 22, 32, 42, 52, 62, 72. But, instead of 52, it is 20 which to be turned out.

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