Online C Programming Test - C Programming Test - Random
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- Total number of questions: 20.
- Time allotted: 30 minutes.
- Each question carries 1 mark; there are no negative marks.
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- All the best!
Marks : 2/20
Test Review : View answers and explanation for this test.
#include<stdio.h>
int main()
{
float a = 0.7;
if(0.7 > a)
printf("Hi\n");
else
printf("Hello\n");
return 0;
}
if(0.7 > a) here a is a float variable and 0.7 is a double constant. The double constant 0.7 is greater than the float variable a. Hence the if condition is satisfied and it prints 'Hi'
Example:
#include<stdio.h>
int main()
{
float a=0.7;
printf("%.10f %.10f\n",0.7, a);
return 0;
}
Output:
0.7000000000 0.6999999881
| 1. | ! |
| 2. | sizeof |
| 3. | ~ |
| 4. | && |
An operation with only one operand is called unary operation.
Unary operators:
! Logical NOT operator.
~ bitwise NOT operator.
sizeof Size-of operator.
&& Logical AND is a logical operator.
Therefore, 1, 2, 3 are unary operators.
No, Two different operators may have same associativity.
Example:
Arithmetic operators like ++, -- having Right-to-Left associativity.
Relational operators like >, >= also have Left-to-Right associativity.
#include<stdio.h>
#include<stdlib.h>
int main()
{
int i=0;
i++;
if(i<=5)
{
printf("IndiaBIX");
exit(1);
main();
}
return 0;
}
Step 1: int i=0; The variable i is declared as in integer type and initialized to '0'(zero).
Step 2: i++; Here variable i is increemented by 1. Hence i becomes '1'(one).
Step 3: if(i<=5) becomes if(1 <=5). Hence the if condition is satisfied and it enter into if block statements.
Step 4: printf("IndiaBIX"); It prints "IndiaBIX".
Step 5: exit(1); This exit statement terminates the program execution.
Hence the output is "IndiaBIx".
No, In a function two return statements can occur but not successively.
Example:
#include <stdio.h>
int mul(int, int); /* Function prototype */
int main()
{
int a = 0, b = 3, c;
c = mul(a, b);
printf("c = %d\n", c);
return 0;
}
/* Two return statements in the mul() function */
int mul(int a, int b)
{
if(a == 0 || b == 0)
{
return 0;
}
else
{
return (a * b);
}
}
Output:
c = 0
#include<stdio.h>
int main()
{
int x=30, *y, *z;
y=&x; /* Assume address of x is 500 and integer is 4 byte size */
z=y;
*y++=*z++;
x++;
printf("x=%d, y=%d, z=%d\n", x, y, z);
return 0;
}
#include<stdio.h>
int main()
{
void fun(int, int[]);
int arr[] = {1, 2, 3, 4};
int i;
fun(4, arr);
for(i=0; i<4; i++)
printf("%d,", arr[i]);
return 0;
}
void fun(int n, int arr[])
{
int *p=0;
int i=0;
while(i++ < n)
p = &arr[i];
*p=0;
}
Step 1: void fun(int, int[]); This prototype tells the compiler that the function fun() accepts one integer value and one array as an arguments and does not return anything.
Step 2: int arr[] = {1, 2, 3, 4}; The variable a is declared as an integer array and it is initialized to
a[0] = 1, a[1] = 2, a[2] = 3, a[3] = 4
Step 3: int i; The variable i is declared as an integer type.
Step 4: fun(4, arr); This function does not affect the output of the program. Let's skip this function.
Step 5: for(i=0; i<4; i++) { printf("%d,", arr[i]); } The for loop runs untill the variable i is less than '4' and it prints the each value of array a.
Hence the output of the program is 1,2,3,4
#include<stdio.h>
int main()
{
enum value{VAL1=0, VAL2, VAL3, VAL4, VAL5} var;
printf("%d\n", sizeof(var));
return 0;
}
#include<stdio.h>
int main()
{
int a=250;
printf("%1d \n", a);
return 0;
}
int a=250; The variable a is declared as an integer type and initialized to value 250.
printf("%1d \n", a); It prints the value of variable a.
Hence the output of the program is 250.
#include<stdio.h>
int main()
{
int i;
printf("%d\n", scanf("%d", &i));
return 0;
}
The scanf function returns the number of input is given.
printf("%d\n", scanf("%d", &i)); The scanf function returns the value 1(one).
Therefore, the output of the program is '1'.
#include<stdio.h>
int main()
{
FILE *fptr;
char str[80];
fptr = fopen("f1.dat", "w");
if(fptr == NULL)
printf("Cannot open file");
else
{
while(strlen(gets(str))>0)
{
fputs(str, fptr);
fputs("\n", fptr);
}
fclose(fptr);
}
return 0;
}
This program get the input string from the user through gets function and store it in the file f1.txt using fputs function.
#include<stdio.h>
void fun(int);
int main(int argc)
{
printf("%d ", argc);
fun(argc);
return 0;
}
void fun(int i)
{
if(i!=4)
main(++i);
}
/* myproc.c */
#include<stdio.h>
int main(int argc, char *argv[])
{
printf("%s", argv[0]);
return 0;
}
#include<stdio.h>
#include<stdlib.h>
int main()
{
union test
{
int i;
float f;
char c;
};
union test *t;
t = (union test *)malloc(sizeof(union test));
t->f = 10.10f;
printf("%f", t->f);
return 0;
}
itoa() takes the integer input value input and converts it to a number in base radix. The resulting number a sequence of base-radix digits.
Example:
/* itoa() example */
#include <stdio.h>
#include <stdlib.h>
int main ()
{
int no;
char buff [50];
printf ("Enter number: ");
scanf ("%d",&no);
itoa (no,buff,10);
printf ("Decimal: %s\n",buff);
itoa (no,buff,2);
printf ("Binary: %s\n",buff);
itoa (no,buff,16);
printf ("Hexadecimal: %s\n",buff);
return 0;
}
Output:
Enter a number: 1250
Decimal: 1250
Binary: 10011100010
Hexadecimal: 4e2